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That was my intention, but I had second thoughts because I measured out that between SW and L(-) has 1/2 of sources voltage. So no need for any isolation?
Not quite what I was looking for. I was a bit unclear with my setup. The lock is Abloy EL581 and has a bolt with 2 states. It's either in or out.
Lock is already powered up from another circuit so basicly I just need a locking state (in this case NO (=Open) is enough). Shelly output goes to access controllers "open button" and it opens the lock.
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Only difference is that I'm using 12 VDC and the input sensor is normally open information from the lock.
So I want to have lock state (open/locked) to Shelly, but I don't want to send any current to lock. Do I need like a optocoupler between lock and SW / L(-)?